Asked by kesha
What's the speed of the Hubble telescope when it is in orbit 598 km above the earths surface?
Answers
Answered by
bobpursley
Its period is 96 min, so velcity must be...
velocity= 2PIradius/time=2PI(radEarth+598,000)/96
be certain to put radius Earth in meters to get velocity in m/min.
velocity= 2PIradius/time=2PI(radEarth+598,000)/96
be certain to put radius Earth in meters to get velocity in m/min.
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