Question
intersect x^2+y^2=36-8x^2-8y^2
Answers
Reiny
with .... ?
Anonymous
x^2+y^2=36-8x^2-8y^2
x^2+8x^2+y^2+8y^2=36
9x^2+9y^2=36 Divide both sides with 9
x^2+y^2=4
That is circle.
x^2+y^2=R^2
Coordinates of center: 0,0
Radius: R=2
Intersect:
For x=0 y^2=4, y=sqrt(4)= +or- 2
For y=0 x^2=4, x=sqrt(4)= +or- 2
x^2+8x^2+y^2+8y^2=36
9x^2+9y^2=36 Divide both sides with 9
x^2+y^2=4
That is circle.
x^2+y^2=R^2
Coordinates of center: 0,0
Radius: R=2
Intersect:
For x=0 y^2=4, y=sqrt(4)= +or- 2
For y=0 x^2=4, x=sqrt(4)= +or- 2