Question

intersect x^2+y^2=36-8x^2-8y^2

Answer 1

with .... ?

Answer 2

x^2+y^2=36-8x^2-8y^2

x^2+8x^2+y^2+8y^2=36

9x^2+9y^2=36 Divide both sides with 9

x^2+y^2=4


That is circle.

x^2+y^2=R^2

Coordinates of center: 0,0

Radius: R=2

Intersect:

For x=0 y^2=4, y=sqrt(4)= +or- 2


For y=0 x^2=4, x=sqrt(4)= +or- 2