Asked by denise
what is an equation of the line containing the given point and prallel to the given line; (5,-2);6x-7y=4
Answers
Answered by
Max
First, put the equation in slope-intercept form.
6x-7y=4
-7y=-6x+4
-y=-6/7x+4/7
y=6/7x-4/7
So the slope of the parallel line will also be 6/7.
Now use the point slope formula to find the
equation of the line.
y-y1=m(x-x1)
y-(-2)=6/7(x-5)
y+2=6/7(x-5)
y+2=6/7x-30/7
y=6/7x-44/7
That is the equation of the line.
6x-7y=4
-7y=-6x+4
-y=-6/7x+4/7
y=6/7x-4/7
So the slope of the parallel line will also be 6/7.
Now use the point slope formula to find the
equation of the line.
y-y1=m(x-x1)
y-(-2)=6/7(x-5)
y+2=6/7(x-5)
y+2=6/7x-30/7
y=6/7x-44/7
That is the equation of the line.