Asked by lisa

[1-sin^2(alfa+beta)]/cos^2(alfa+beta)

14 years ago

Answered by Reiny

[1-sin^2(alfa+beta)]/cos^2(alfa+beta)
= cos^2(alfa+beta) / cos^2(alfa+beta)
= 1

(remember .... 1 - sin^2 x = cos^2 x)

14 years ago

Answered by bobpursley

remember that 1=sin^2 Theta + cos^2 Theta, so

1-sin^2 Theta=cos^2 theta

14 years ago

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