Asked by aditya
the volume of nh3 at stp needed to pass into 30 ml of 1N h2so4 solution to bring down its strength to m/10
Answers
Answered by
Chethan
Meq of original H2SO4=30×1=30
Meq of H2SO4 after passing NH3=30×0.2=6
Meq of H2SO4 lost =30−6=24
Meq of NH3 passed=Meq of H2SO4 lost
w17×1000=24
WNH3=0.408g
∴ Volume of NH3 at STP=22.4×0.40817
⇒0.5376l
⇒537.6ml
Meq of H2SO4 after passing NH3=30×0.2=6
Meq of H2SO4 lost =30−6=24
Meq of NH3 passed=Meq of H2SO4 lost
w17×1000=24
WNH3=0.408g
∴ Volume of NH3 at STP=22.4×0.40817
⇒0.5376l
⇒537.6ml
Answered by
nidhish mishra
PAAAAAAAAGLU Answer dene k liye sukkriyaa
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