I think you can look at this problem like this.
Each year it is 2,16 * 10^13 kg more CO2 put into the atmosphere, and this is
2,16*10^13/4,5*10^15 = 0,005 increase.
So if you use a simple interest formula you should get the right answer. (same growth each year)
4,5 * 1,005^x = 9 (10^15 cancels out)
1,005^x = 2
x*log(1,005) = log(2)
x = log(2)/log(1,005)
x = 139
So it would take 139 years for the CO2 amount to double in the atmosphere, with the current use of fossil fuel.
What volume of air is needed to burn an entire 60-L (approximately 16-gal) tank of gasoline? Assume that the gasoline is pure octane, C8H18. Hint: air is 20% oxygen by volume, 1 mol of a gas occupies about 25 L at room temperature, and the density of octane is 0.70 g/cm3.
1 answer