Question

In an experiment, a seabird was taken from its nest, flown a distance 5190 km away, and released. It found its way back to its nest a time 13.8 days after release.

What was the bird's average velocity in m/s for the whole episode, from leaving the nest to returning?

Would I double the distance traveled?

Answer 1

Although you could calculate the velocity for the return, there is no information to calculate the velocity for the trip from the nest. How fast did the plane fly?

Answer 2

The time given was the time spent away from the nest after release. We don't know the time spent away from the nest before it was released. I would not double the distance,because the bird did not fly away from the nest; it was
flown.

5190km * 1000m/km = 5,190,000m.

V=(5,190,000m / 13.8days)*(1/24)days /h
* (1/3600)h/s = 4.35m/s.