60=80(1-e-.3x)
3/5=1-e^-.3x)
2/5=e^-.3x
ln (2/5)=-3.x
Surely you can solve it from here. This is hardly calculus.
After x weeks of prcatice, a student can type f(x)=80(1-e^-0.3x)words a minute. How sooon will the student be able to type 60 words per minute? (Round to the nearest tenth)
1 answer