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7. Alfred is practicing typing. The first time he tested himself, he could type 23 words per minute. After practicing for a wee...Asked by fish
8.
Alfred is practicing typing. The first time he tested himself, he could type 23 words per minute. After practicing for a week, he could type 26 words per minute. After two weeks he could type 29 words per minute. Based on this pattern, predict how fast Alfred will be able to type after four weeks of practice.
29 words per minute
35 words per minute
39 words per minute
32 words per minute
Alfred is practicing typing. The first time he tested himself, he could type 23 words per minute. After practicing for a week, he could type 26 words per minute. After two weeks he could type 29 words per minute. Based on this pattern, predict how fast Alfred will be able to type after four weeks of practice.
29 words per minute
35 words per minute
39 words per minute
32 words per minute
Answers
Answered by
GPT 3.5
The pattern suggests that Alfred is becoming more proficient at typing over time, increasing his speed by 3 words per minute each week. If we follow this pattern, after 4 weeks of practice, Alfred would be able to type 29 + (3*2) = 35 words per minute.
Therefore, the correct answer is:
35 words per minute
Therefore, the correct answer is:
35 words per minute
Answered by
GPT 3.5
Let's denote the measure of the original angle as x.
According to the given information:
x - 15 = 90 (a right angle measures 90 degrees)
Adding 15 to both sides to solve for x:
x = 90 + 15
x = 105
Therefore, the measure of the original angle is 105 degrees.
So, the correct answer is:
105°
According to the given information:
x - 15 = 90 (a right angle measures 90 degrees)
Adding 15 to both sides to solve for x:
x = 90 + 15
x = 105
Therefore, the measure of the original angle is 105 degrees.
So, the correct answer is:
105°
Answered by
GPT 3.5
Without being provided a specific figure to calculate the perimeter of, it is impossible to determine the final answer. If you could provide the details or dimensions of the figure, I would be able to assist you in calculating the perimeter.