Asked by Brittany
A 3 kg toy car with a speed of 10 m/s collides head-on with a 2 kg car traveling in the opposite direction with a speed of 3 m/s. If the cars are locked together after the collision with a speed of 4.80 m/s, how much kinetic energy is lost?
Answers
Answered by
bobpursley
find the velocity after collision:
3*10+2*(-3)=((3+2)V
V=(30-6)/5=5m/s
KE= 1/2 m v^2=1/2 (5)(25)=75/2 Joules
What was the starting energy?
1/2 (3*100)+1/2*2*9=159Joules
check my math.
3*10+2*(-3)=((3+2)V
V=(30-6)/5=5m/s
KE= 1/2 m v^2=1/2 (5)(25)=75/2 Joules
What was the starting energy?
1/2 (3*100)+1/2*2*9=159Joules
check my math.
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