Asked by Anonymous
What is the take off speed of a locust if its launch at an angle of 60 and its range 88m. Also calculate the time of flight (g=10m)
Answers
Answered by
Henry
1. R = Vo^2sin(2A)/g,
Vo^2 = R / sin(2A)/g,
Vo^2 = 88 / sin(120)/10 = 1016,
Vo = 31.88m/s.
2. R = Vo*cosA * T,
T = R / Vo*cosA,
T = 88 / (31.88cos60) = 5.52s.
Vo^2 = R / sin(2A)/g,
Vo^2 = 88 / sin(120)/10 = 1016,
Vo = 31.88m/s.
2. R = Vo*cosA * T,
T = R / Vo*cosA,
T = 88 / (31.88cos60) = 5.52s.
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