Asked by Mary
What is the mass (in g) of 4.65x10^22 molecules of P4O10? ( I already calculated it and the answer is 0.1 grams of P4O10.) How many P atoms are present in this sample? Thank you!
Answers
Answered by
DrBob222
You have 4.65E22 molecules of P4O10. There are 10 O atoms in 1 molecules so there must be 4.65E22 x 10 = ?? atoms of O. I don't agree with your answer for th number of grams. Since there are 6.022E23 molecules in a mole, 4.65E22 molecules is
4.65E22 x (1 mole/6.022E23) = ?? moles P4O10. Then grams = moles x molar mass.
4.65E22 x (1 mole/6.022E23) = ?? moles P4O10. Then grams = moles x molar mass.
Answered by
Muhammad Waqar Khokhar
The formula of the question is given molecules / NA x molar mass of compound
So we gain the mass of compound is 22g of P4O10
So we gain the mass of compound is 22g of P4O10
Answered by
Amos
1 mole of P4O10= 6•022×10^23.
Mass/284(molar mass) of P4O10 = 4•65×10^22.
Therefore Mass =284×(4•65×10^22)/(6.022×10^23).
The answer is 21.9g
Mass/284(molar mass) of P4O10 = 4•65×10^22.
Therefore Mass =284×(4•65×10^22)/(6.022×10^23).
The answer is 21.9g
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