Asked by Tc

Need help with my lab report for specific heat of unknown metal!

I need to Find the Specific Heat of Al! I know its Q= M x Cs x Change in Temp

I am getting a such a high number am just confused if its right.

Here is what I got in Lab:

Aluminum

Mass of Metal (Mm): 6.128g
Mass of water (Mw) : 25 mL
Temp of water in calorimeter: 23.6 C
Temp of metal in water-bath: 100 C
T Final: 28.4 C

PLS helppp.... i am stuck on this!
Answered by drwls
The heat gained by the water in reaching equilibrium equals the heat lost by the metal. Assume that you know the specific heat of water is Cwater = 1.00 cal/g*C.
Cmetal*6.128*(100-28.4) = Cwater*25*(28.4-23.6)
Cmetal = 1.00*25*4.8)/[6.128*71.6]
= 0.274 cal/(g*C)
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