Asked by Nozomi
The following is a report of defective parts reported by inspectors in 3 electronic factories:
Brookline= 3 per 10,000
Brookville= 5 per 100,000
Brooklyn= 13 per 1,000,000
Which of the following best expresses the portion of defective parts in three factories combined:
(A) 5 per 10,000
(B) 66 per 10,000
(C) 66 per 100,000
(D) 93 per 1,000,000
(E) 363 per 1,000,000
Brookline= 3 per 10,000
Brookville= 5 per 100,000
Brooklyn= 13 per 1,000,000
Which of the following best expresses the portion of defective parts in three factories combined:
(A) 5 per 10,000
(B) 66 per 10,000
(C) 66 per 100,000
(D) 93 per 1,000,000
(E) 363 per 1,000,000
Answers
Answered by
Stephen
3 per 10,000 becomes 30 per 100,000
35 per 100,00 becomes 350 per 1,000,000
350 + 13 becomes 363 per million
35 per 100,00 becomes 350 per 1,000,000
350 + 13 becomes 363 per million
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