Asked by Kay
Find the integral of:
f(x)= (x^4 + 2 sqrt x )/x^2
I tried...
= x^2 + 2 sqrt x / x^2
= x^2 + 2 x^-1.5
=1/3 x^3 + ???
f(x)= (x^4 + 2 sqrt x )/x^2
I tried...
= x^2 + 2 sqrt x / x^2
= x^2 + 2 x^-1.5
=1/3 x^3 + ???
Answers
Answered by
Reiny
first term is fine.
f(x) = (x^4 + 2x^(1/2))/x^2
= x^2 + 2x^(-1.5)
integral of that is
(1/3)x^3 - (4/5)x^(-1/2) + constant , (remember, we have to raise the exponent by 1)
= (1/3)x^3 - 4/(5√x) + constant
f(x) = (x^4 + 2x^(1/2))/x^2
= x^2 + 2x^(-1.5)
integral of that is
(1/3)x^3 - (4/5)x^(-1/2) + constant , (remember, we have to raise the exponent by 1)
= (1/3)x^3 - 4/(5√x) + constant
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