Asked by Jessica
A can of soda is placed inside a cooler. As the soda cools, its temperature T(x) in degrees Celsius is given by the following exponential function, where is the number of minutes since the can was placed in the cooler.
T(x)=-22+44e^-0.03x
Find the initial temperature of the soda and its temperature after 18 minutes. Round your answers to the nearest degree as necessary.
Initial temp=
After 18 minutes =
T(x)=-22+44e^-0.03x
Find the initial temperature of the soda and its temperature after 18 minutes. Round your answers to the nearest degree as necessary.
Initial temp=
After 18 minutes =
Answers
Answered by
Henry
T(x) = -22 + 44*e^(-0.03x).
T(o) = -22 + 44*e^(-0.03*0),
T(o) = -22 + 44*e^0 = -22 + 44*1 = 22deg C.
T(18) = -22 + 44*e^(-0.03*18),
T(18) = -22 + 44*0.5827 = 4 deg C.
T(o) = -22 + 44*e^(-0.03*0),
T(o) = -22 + 44*e^0 = -22 + 44*1 = 22deg C.
T(18) = -22 + 44*e^(-0.03*18),
T(18) = -22 + 44*0.5827 = 4 deg C.
Answered by
John
T(x) =
Answered by
John
A can of soda is placed inside a cooler. As the soda cools, its temperature
Tx
in degrees Celsius is given by the following function, where
x
is the number of minutes since the can was placed in the cooler.
T(x) = -17+39e^-0.45
Tx
in degrees Celsius is given by the following function, where
x
is the number of minutes since the can was placed in the cooler.
T(x) = -17+39e^-0.45
Answered by
Anonymous
poop= T (x) = - 17 + 39e^-0.45
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