Asked by chris
a can of soda at 80 F is placed in a refrigerator that maintains a constant temperature of 37 F the temperature T of the soda t minutes after it is placed in the refrigerator is given by
T(t)=37+43e^-0.058t
find temp to the nearest degree of the soda after 7 minutes
when to the nearest minute will the temp of the soda be 43 F
T(t)=37+43e^-0.058t
find temp to the nearest degree of the soda after 7 minutes
when to the nearest minute will the temp of the soda be 43 F
Answers
Answered by
Steve
T(7) = 37+43e^-0.058(7) = 65.65
43 = 37+43e^-0.058t
6/43 = .1395 = e^-0.058t
ln .1395 = -.058t
−1.9696 = -.058t
t = 33.96
43 = 37+43e^-0.058t
6/43 = .1395 = e^-0.058t
ln .1395 = -.058t
−1.9696 = -.058t
t = 33.96
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