Question
a body is released from a height and falls freely towards the earth. exactly one sec later another body is released.what is the distance between the two bodies 2sec after the release of the second body. if g=9.8m/s^2.
Answers
bobpursley
hf1 is the final height of first
hf2 is the final height of second.
so,the question is
hf1-hf2=ho1-4.9t^2-ho2+4.9(t-1)^2
t=2; ho1=ho2
hf2 is the final height of second.
so,the question is
hf1-hf2=ho1-4.9t^2-ho2+4.9(t-1)^2
t=2; ho1=ho2
Related Questions
a body is released from the great height and falls freely towards the earth . another body is releas...
A body of mass 2kg is released from rest and falls freely under gravity.find it's speed when it has...
A body mass 2kg falls freely through a height of 50m and comes to rest having penetration 5.0 of san...
A body of mass 2kg is released from rest and falls
freely under gravity. Find its speed when it has...