Asked by pavatharani
a body is released from a height and falls freely towards the earth. exactly one sec later another body is released.what is the distance between the two bodies 2sec after the release of the second body. if g=9.8m/s^2.
Answers
Answered by
bobpursley
hf1 is the final height of first
hf2 is the final height of second.
so,the question is
hf1-hf2=ho1-4.9t^2-ho2+4.9(t-1)^2
t=2; ho1=ho2
hf2 is the final height of second.
so,the question is
hf1-hf2=ho1-4.9t^2-ho2+4.9(t-1)^2
t=2; ho1=ho2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.