Question
The following logistic function describes the percent of the population of a city that will purchase the local newspaper.
P(t)=(65)/(1+34e^(-0.223 t))
"t" is the number of days since the newspaper is first launched.
When will the newspaper reach 60% of the population
P(t)=(65)/(1+34e^(-0.223 t))
"t" is the number of days since the newspaper is first launched.
When will the newspaper reach 60% of the population
Answers
drwls
Solve 60 = (65)/(1+34e^(-0.223 t))
(1+34e^(-0.223 t)) = 65/60 = 1.0833
34 e^(-0.223 t) = 0.0833
e^(-0.223 t) = 2.25*10^-3
-.223 t = -6.01
t = 27 days
(1+34e^(-0.223 t)) = 65/60 = 1.0833
34 e^(-0.223 t) = 0.0833
e^(-0.223 t) = 2.25*10^-3
-.223 t = -6.01
t = 27 days