Asked by Deb

determine half life of krypton-92 if only 6.0 millograms of an original 96.0 sample remains unchanged after 7.36 seconds
Answered by DrBob222
ln(No/N) = kt
No = 96
N = 6
k = unknown
t = 7.36 seconds.
Then substitute k into the below equation.
k = 0.693/t<sub>1/2</sub> and solve for t<sub>1/2</sub>.
Answered by g
1.84 seconds
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