Asked by niki
at 40 degree C , the vapour pressure of water is 55.3 mm of hg. calculate the vapour pressure at same temp. of 10%aques solution of urea??
Answers
Answered by
DrBob222
P<sub>H2O</sub> = X<sub>soln</sub>*P<sup>o</sup><sub>H2O</sub>
10% urea = 10g urea/(10g urea+90g H2O)
moles urea = grams/molar mass urea.
moles H2O = grams/molar mass H2O.
X<sub>H2O</sub> = moles H2O/total moles.
Then plug this X for H2O into the equation at the top, multiply by 55.3 mm.
10% urea = 10g urea/(10g urea+90g H2O)
moles urea = grams/molar mass urea.
moles H2O = grams/molar mass H2O.
X<sub>H2O</sub> = moles H2O/total moles.
Then plug this X for H2O into the equation at the top, multiply by 55.3 mm.
Answered by
DrBob222
The first equation should read this way.
Psoln = XH2O*PoH2O
Psoln = XH2O*PoH2O
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