Asked by paul
At 25°C the vapour pressure of pure pentane is 511 torr and that of hexane is 150. torr.
What is the mole fraction of pentane in a pentane-hexane solution that has a vapour pressure of 333 torr at 25°C?
What is the mole fraction of pentane in a pentane-hexane solution that has a vapour pressure of 333 torr at 25°C?
Answers
Answered by
DrBob222
ppen = Xpen*P<sup>o</sup><sub>pentane</sub>
phex = Xhex*P<sup>o</sup><sub>hexane</sub>
(511*Xpen) + (150*Xhex) = 333
(511*Xp) + 150(1-Xp) = 333
Solve for Xpentane and Xhexane.
phex = Xhex*P<sup>o</sup><sub>hexane</sub>
(511*Xpen) + (150*Xhex) = 333
(511*Xp) + 150(1-Xp) = 333
Solve for Xpentane and Xhexane.
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