Asked by paul
At 25°C the vapour pressure of pure pentane is 511 torr and that of hexane is 150. torr.
What is the mole fraction of pentane in a pentane-hexane solution that has a vapour pressure of 333 torr at 25°C?
What is the mole fraction of pentane in a pentane-hexane solution that has a vapour pressure of 333 torr at 25°C?
Answers
Answered by
DrBob222
ppen = Xpen*P<sup>o</sup><sub>pentane</sub>
phex = Xhex*P<sup>o</sup><sub>hexane</sub>
(511*Xpen) + (150*Xhex) = 333
(511*Xp) + 150(1-Xp) = 333
Solve for Xpentane and Xhexane.
phex = Xhex*P<sup>o</sup><sub>hexane</sub>
(511*Xpen) + (150*Xhex) = 333
(511*Xp) + 150(1-Xp) = 333
Solve for Xpentane and Xhexane.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.