Asked by Christina
A stationary roller coaster at the top of its path is 30m about the ground. The car and its passengers have a mass of 400kg. What is the velocity of the car when it reaches the ground lever? The formula for velocity is (Distance/time)
Answers
Answered by
bobpursley
the gain in Kinetic energy is equal to the loss of potential energy
1/2 m v^2=mgh
solve for v
1/2 m v^2=mgh
solve for v
Answered by
Damon
mass cancels out, irrelevant
m g h = (1/2) m v^2
2 g h = v^2
v = sqrt (2 g h)
v = sqrt (2*9.8*30)
v = 24.2 m/s
m g h = (1/2) m v^2
2 g h = v^2
v = sqrt (2 g h)
v = sqrt (2*9.8*30)
v = 24.2 m/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.