A 600.0 kg roller coaster is going around vertical loop with a radius of 10.0 meters. The speed of the coaster is 14m/s at the top of the loop.

What it the magnitude of the CENTRIPETAL force on the roller coaster, to the nearest whole number of newtons?

Fc=mv^2/r
600.0kg(14)^2/10.0=
Answer: 11760 N
Am I correct?

1 answer

looks good

are significant figures an issue?