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I'm trying to figure out the formula for one liter of 1M K2HPO4 (Potassium Phosphate Dibasic). I know the amount of K2HPO4 is 174.18grams and you make it to equal one liter with dH2O, but I can't find where anyone has actually written the amount of dH2O to use. Without actually making it, can some one please help?
DrBob222
answered
13 years ago
13 years ago