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Three times the reciprocal of the sum of two consecutive odd integers is 3/20. Find the two consecutive off integers.
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Answered by
MathMate
Let 2n-1 be the smaller odd integer, then
2n+1 is the larger.
Given
3/(2n-1 + 2n+1)=3/20
3/(4n)=3/20
4n=20
n=5
The integers are 2*5-1=9 and 2*5+1=11.
2n+1 is the larger.
Given
3/(2n-1 + 2n+1)=3/20
3/(4n)=3/20
4n=20
n=5
The integers are 2*5-1=9 and 2*5+1=11.
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