Question

50.00 mL of 1.0 M HCl and 50.00 mL of 1.0 M NaOH are mixed. The temperature is observed to increase by 10.0 degrees C. How much energy (in J) was absorbed by the calorimeter? Assume a density of the reaction mixture of 1 g/mL. Specific heat of the solution is 5.00 J/g/degree C. The calorimeter constant is 10.0 J/degree C.

Answer 1

The energy absorbed by the calorimeter itself is constant x delta T = 10 x 10.
The energy absorbed by the calorimeter AND the contents is
[mass soln x specific heat soln x delta T] + [Ccal x delta T}= ??