Asked by destiny
: what is the Ka of butanoic acid whose pka is4.82?
show workkkk please
show workkkk please
Answers
Answered by
DrBob222
pH = -log(H^+) and
pOH = -log(OH^-).
Likewise,
pKa = -log(Ka), so
4.82 = -log Ka
log Ka = -4.82
Ka = 1.51E-5
pOH = -log(OH^-).
Likewise,
pKa = -log(Ka), so
4.82 = -log Ka
log Ka = -4.82
Ka = 1.51E-5
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