Asked by kay
Given the following sets, select the statement below that is NOT true.
A = {b,l,a,z,e,r}, B = {b,a,l,e}, C = {a,b,l,e}, D = {l,a,b}, E = {a,b,l}
E C
E B
D B
B C
C A
I chose the last one. Did I choose correctly?
A = {b,l,a,z,e,r}, B = {b,a,l,e}, C = {a,b,l,e}, D = {l,a,b}, E = {a,b,l}
E C
E B
D B
B C
C A
I chose the last one. Did I choose correctly?
Answers
Answered by
MathMate
I cannot interpret the symbol between the sets in the answers.
However, by looking at the answers, I suppose it is the symbol ⊂ which means "is a proper subset of".
If A⊂B, A is a proper subset of B, means that all elements of A are also elements of B, <i>and</i> such that A≠B, i.e. the cardinality of A must be <i>less than </i> the cardinality of B.
Out of the 5 responses, all the elements of the first set are in the second set. However, there is one case where the two set contain identical elements, i.e. they also have the same number of elements.
Can you find which case?
However, by looking at the answers, I suppose it is the symbol ⊂ which means "is a proper subset of".
If A⊂B, A is a proper subset of B, means that all elements of A are also elements of B, <i>and</i> such that A≠B, i.e. the cardinality of A must be <i>less than </i> the cardinality of B.
Out of the 5 responses, all the elements of the first set are in the second set. However, there is one case where the two set contain identical elements, i.e. they also have the same number of elements.
Can you find which case?
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