Asked by Sean
Find the exact solutions to each equation for the interval [0,360)
2cosx-secx = 1
2cosx-secx = 1
Answers
Answered by
Reiny
2 cosx - 1/cosx = 1
(2cos^2 x - 1)cosx = 1
2cos^2 x - 1 = cosx
2cos^2 x - cosx - 1 = 0
(2cosx + 1)(cosx-1) = 0
cosx = -1/2 or cosx = 1
x = 120º, 240º,0º,360º
(2cos^2 x - 1)cosx = 1
2cos^2 x - 1 = cosx
2cos^2 x - cosx - 1 = 0
(2cosx + 1)(cosx-1) = 0
cosx = -1/2 or cosx = 1
x = 120º, 240º,0º,360º
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