Asked by el
the enthalpy of fusion of ice is 6.02 kJ/mol. the heat capacity of liquid water is 75.4 J/molC. What is the smallest number of ice cubes at 0 degrees C each containing one mole of water, necessary to cool 500g of liquid water initially at 20.0 degree C to 0.0 degree C
Answers
Answered by
DrBob222
(mass ice*heat fusion) + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
Solve for mass ice then convert to number of cubes. Remember 1 mole water = 18 grams. The way I read the problem, they don't want any fractional ice cubes. If my interpretation is correct you will calculate the number of ice cubes, then round to the next higher whole number.
Solve for mass ice then convert to number of cubes. Remember 1 mole water = 18 grams. The way I read the problem, they don't want any fractional ice cubes. If my interpretation is correct you will calculate the number of ice cubes, then round to the next higher whole number.
Answered by
e
egw
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