sum of heats gained=0
heat gained by ice+heatgained by water=0
N*6020 + (500/18)*75.4*(0-20)=0
solve for N, take the next highest whole number.
The enthalpy of fusion of ice is 6.020 kJ/mol. The heat capacity of liquid water is 75.4 J/mol degrees Celsius. What is the smallest number of ice cubes at 0 degrees Celsius, each containing one mole of water, necessary to cool 500. g of liquid water initially at 20 degrees Celsius to 0 degrees Celsius?
2 answers
very good question and it is very nicely answered and thanks for the answer