Asked by Anonymous
a rocket is launched from atop a 105-foot cliff with an initial velocity of 156 ft/s.The height of the rocket above the ground at time or t is given by h=-16tsquared+156t+105. When will the rocket hit the ground after it is launched?
Answers
Answered by
bobpursley
when is h= 0?
0=h(t)=-16t^2 + 156t+105
solve for t.
0=h(t)=-16t^2 + 156t+105
solve for t.
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