Asked by corey
There are 6 boys and 8 girls in a group of students. Calculate the number of ways that a president, vice-president and treasurer can be selected.
Please show your work.
Please show your work.
Answers
Answered by
MathMate
14 students in all, no one student can occupy two posts.
Choose a president from 14 students, a vice-president from 13 remaining students, and a treasurer from the 12 remaining students.
There are six (3!) ways to "shuffle" the three posts, so
for a total of
14*13*12/3! = C(14,3) = 14!/((14-3)!3!)
ways
Choose a president from 14 students, a vice-president from 13 remaining students, and a treasurer from the 12 remaining students.
There are six (3!) ways to "shuffle" the three posts, so
for a total of
14*13*12/3! = C(14,3) = 14!/((14-3)!3!)
ways
Answered by
MathMate
14 students in all, no one student can occupy two posts.
Choose a president from 14 students, a vice-president from 13 remaining students, and a treasurer from the 12 remaining students.
Number of ways to choose three distinct posts
=14*13*12
=14!/(14-3)!
Choose a president from 14 students, a vice-president from 13 remaining students, and a treasurer from the 12 remaining students.
Number of ways to choose three distinct posts
=14*13*12
=14!/(14-3)!
Answered by
corey
thank you so much!
Answered by
MathMate
You're welcome!
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