Asked by corey

There are 6 boys and 8 girls in a group of students. Calculate the number of ways that a committee of 3 students which has at least 1 girl can be selected from the group.

Please show your work.

Answers

Answered by MathMate
Number of ways to choose 3 students from 14 = C(14,3) = 14!/((14-3)!3!)

Number of ways to choose 3 students from 8 boys = C(8,3) = 8!/((8-3)!3!)

Number of ways to choose 3 students with at least one girl
= C(14,3)-C(8,3)
Answered by corey
thank you!
Answered by MathMate
You're welcome!
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