E = hc/wavelength.
You don't need to go through the frequency if you use the above equation. Wavelength must be inserted in meters.
HINT: From the wavelength and the speed of light, we can get the frequency. Then the energy is simply hf. Use Planck's constant h in the proper units.
You don't need to go through the frequency if you use the above equation. Wavelength must be inserted in meters.
E = hc/w. h has units J*s. c is m/s. w is in m so we have J*s*m/s/m. m and s cancel to leave E in J.
First, we need to find the frequency of the light using the equation:
c = λf
Where c is the speed of light, λ is the wavelength, and f is the frequency.
Given that the speed of light is approximately 3.00 x 10^8 m/s, and the wavelength is 0.67 μm (0.67 x 10^-6 m), we can rearrange the equation to solve for f:
f = c/λ
Substituting the values, we have:
f = (3.00 x 10^8 m/s) / (0.67 x 10^-6 m)
Now, let's solve for f:
f ≈ 4.48 x 10^14 Hz
Now that we have the frequency, we can calculate the energy of the photon using the equation E = hf.
Given that Planck's constant, h, is approximately 6.63 x 10^-34 J·s, we can rearrange the equation to solve for E:
E = hf
Substituting the values, we have:
E = (6.63 x 10^-34 J·s) x (4.48 x 10^14 Hz)
Now, let's solve for E:
E ≈ 2.97 x 10^-19 J
So, the energy of a photon with a wavelength of 0.67 μm is approximately 2.97 x 10^-19 Joules.