Question

If 15.omL of 0.0250 M aqueous H2SO4 is required to neutralize 10.0 mL of aqueous solution of KOH, what is the molarity of the KOH solution?
2KOH + H2SO4 ==> K2SO4 + 2H2O
moles H2SO4 = M x L = ??
Convert moles H2SO4 to moles KOH. It will be ??mole H2SO4 x 2 = moles KOH.
M KOH = moles KOH/L KOH
BMAVA=AMBVB 2(0. 25)(15)=1(10)(MB) 0.75/10=10MB/10 MB=0.075M ANSWERED
.25

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