Asked by Samantha

What is the pH of a 0.0250 M solution of HCN? Ka = 4.0x10^-10
Answered by bobpursley
HCN >< H+ CN-

.250-x <> x+ x


4E-10=x^2/(.250-x) appx x^2/.250

[H+]= sqrt (4*.250E-10)

= 1E-5

pH= 5
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