Asked by Samantha
What is the pH of a 0.0250 M solution of HCN? Ka = 4.0x10^-10
Answers
Answered by
bobpursley
HCN >< H+ CN-
.250-x <> x+ x
4E-10=x^2/(.250-x) appx x^2/.250
[H+]= sqrt (4*.250E-10)
= 1E-5
pH= 5
.250-x <> x+ x
4E-10=x^2/(.250-x) appx x^2/.250
[H+]= sqrt (4*.250E-10)
= 1E-5
pH= 5