Question

please shoe me how to factor this problem b^3-4b^2-9b+36

Answer 1

use "grouping"

b^3-4b^2-9b+36
= b^2(b-4) - 9(b-4)
= (b-4)(b^2-9)
= (b-4)(b+3)(b-3)

Answer 2

x3 + 2x2 + x + 2