A shoe flung into the air such that at the end of 2.0 m/s it is at its maximum height moving at 6.0 m/s. How far away will it be from the thrower when it returns to the launch altitude.

Answer 1

2.0 what?

Answer 2

2.0 s

Answer 3

by the way at max height, your entire velocity is the horizontal component, u = 6 m/s , which is constant until it hits something.

Answer 4

so it took 2 seconds to stop vertical motion

so it was in the air for 4 seconds

so it went 6 * 4 = 24 meters