Asked by tenzing
during pratice a softball pitcher throws a ball whose height can be modeled by the equation h=-16tsquared+24t+1 where h=height in feet and t=time in seconds. how lond does it take for the ball to reach a height of 6 feet?
Answers
Answered by
Henry
h = -16t^2 + 24t + 1 = 6.
-16t^2 + 24t - 5 = 0,
Solve for t using the Quadratic Formula
and get:
t = 0.25 and 1.25s.
We have 2 positive solutions for which
I have no explanation.
-16t^2 + 24t - 5 = 0,
Solve for t using the Quadratic Formula
and get:
t = 0.25 and 1.25s.
We have 2 positive solutions for which
I have no explanation.
Answered by
john
Hi,
The reason for two answers is that when the ball is thrown upwards, it reaches a maximum height of 8 feet (i got this using calculus). This means that the balls reaches 6 feet both on the way up, and then on the way down. Hence the two solutions.
The reason for two answers is that when the ball is thrown upwards, it reaches a maximum height of 8 feet (i got this using calculus). This means that the balls reaches 6 feet both on the way up, and then on the way down. Hence the two solutions.
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