Asked by Anonymous
planet is in circular orbit around the Sun. Its distance from the Sun is 2.9 times the average distance of Earth from the Sun. What is the period of this planet, in Earth years?
Answers
Answered by
bobpursley
period^2/r^3=1year^2/re^3
so period= sqrt (2.9^3)
so period= sqrt (2.9^3)
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