Which planet’s orbit was Kepler first studying when he began to develop his laws of orbital motion?(1 point)

Responses

User Icon for Bot GPT 3.5 Bot GPT 3.5 answered
1 year ago

Jupiter

anonymous anonymous answered
1 year ago

Which orbital shape did most scientists in the early 1600s think the planets of our solar system have?(1 point)

User Icon for Bot GPT 3.5 Bot GPT 3.5 answered
1 year ago

Most scientists in the early 1600s thought that the planets of our solar system have circular orbits.

anonymous anonymous answered
1 year ago

Which of these describes Kepler’s third law of orbital motion?(1 point)

Responses

T∝a2T∝a2

T3 ∝a2T3 ∝a2

T2 ∝ a3 T2 ∝ a3

T2∝a

User Icon for Bot GPT 3.5 Bot GPT 3.5 answered
1 year ago

The correct answer is: T2 ∝ a3

anonymous anonymous answered
1 year ago

Which is the best description of Earth’s orbit?(1 point)

Responses

User Icon for Bot GPT 3.5 Bot GPT 3.5 answered
1 year ago

The best description of Earth's orbit is roughly elliptical, with the Sun at one of the foci.

anonymous anonymous answered
1 year ago

parabolic

parabolic

circular
circular

almost circular
almost circular

highly elliptical

User Icon for Bot GPT 3.5 Bot GPT 3.5 answered
1 year ago

The correct answer is: almost circular

anonymous anonymous answered
1 year ago

Which statement describes Kepler’s third law of orbital motion?(1 point)

Responses

The square of orbital period is proportional to the semi-major axis.
The square of orbital period is proportional to the semi-major axis.

The orbital period is proportional to the square of the semi-major axis.
The orbital period is proportional to the square of the semi-major axis.

The cube of orbital period is proportional to the square of the semi-major axis.
The cube of orbital period is proportional to the square of the semi-major axis.

The square of orbital period is proportional to the cube of the semi-major axis.
The square of orbital period is proportional to the cube of the semi-major axis.
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User Icon for Bot GPT 3.5 Bot GPT 3.5 answered
1 year ago

The correct answer is: The square of orbital period is proportional to the cube of the semi-major axis.