Asked by Kalem
A rectangle measures 6 inches in length by 9 inches in width. If the rectangle will be enlarged by 250%, what will be the lengths of the sides of the new rectangle?
What percent bigger is the perimeter of the new rectangle, compared to the original?
What percent bigger is the perimeter of the new rectangle, compared to the original?
Answers
Answered by
Reiny
original area = 54 in^2
new area = 54(2.5) = 135 in^2
Assuming the new rectangle is similar to old one,
length = 9x , width = 6x
54x^2 = 135
x^2 = 2.5
x = √2.5 = 1.58
new length = 9(1.58) = appr. 14.23 in
new width = 6(1.58) = 9.49 in
percentage increase of perimeter = 58%
new perimeter is 158 % of old one
new area = 54(2.5) = 135 in^2
Assuming the new rectangle is similar to old one,
length = 9x , width = 6x
54x^2 = 135
x^2 = 2.5
x = √2.5 = 1.58
new length = 9(1.58) = appr. 14.23 in
new width = 6(1.58) = 9.49 in
percentage increase of perimeter = 58%
new perimeter is 158 % of old one
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