Asked by David
A suitcase measures 22 inches long and 16 inches high. What is the diagonal length of the suitcase to the nearest foot.
16^2 + 22^2 = C^2
256 + 484 = C^2
740 = C^2
SQRT of 740 = 27.20 in.
The diagonal length to the nearest foot equals 2.26ft.
16^2 + 22^2 = C^2
256 + 484 = C^2
740 = C^2
SQRT of 740 = 27.20 in.
The diagonal length to the nearest foot equals 2.26ft.
Answers
Answered by
PsyDAG
Nearest foot is 2.
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