Asked by Sue

What is the heat in Joules required to raise the temperature of 100g H20 from 288K to 308K?

Answers

Answered by Jai
to get the heat released or absorbed,
Q = mc(T2-T1)
where
m = mass of substance (units in g)
c = specific heat capacity (units in J/g-K)
T2 = final temperature
T1 = initial temperature
**note: if Q is (-), heat is released and if (+), heat is absorbed

for water c = 4.184 J/g-K
substituting,
Q = 100*4.184*(308-288)
Q = 8368 J

hope this helps~ :)
Answered by Ben
8368J

Related Questions