what is the heat in joules required to melt 25 grams of ice?
2 answers
8350 joules
heat fusion is 6.01 kJ/mol. mols = 25/18 = about 1.38
Then 1.38 x 6.01 = ? kJ. That answer above is VERY close.
Then 1.38 x 6.01 = ? kJ. That answer above is VERY close.
1 answer