Asked by shawn
If cos 0 = - 1/2 and tan 0 > 0, find the quadrant that contains the terminal side of 0, and then find the exact values of the other five trig functions of 0.
Answers
Answered by
Anonymous
The cosine is positive in I and IV
quadrant,negative in II and III quadrant.
The tangent is positive in I and III guadrant,negative in II and IV quadrant.
If cos(theta)<0 cosine is negative
If tan(theta)>0 tangent is positive
Only quadrant where cosine is nagative,and tangent is positive is quadrant III.
sin(theta)= + OR - sqroot[1-cos^2(theta)]
In quadrant III sine is negative so:
sin(theta)= - sqroot[1-cos^2(theta)]
sin(theta)= - sqroot[1-(-1/2)^2]
sin(theta)= - sqroot(1-1/4)
sin(theta)= - sqroot(3/4)
sin(theta)= - sqroot(3) /2
tan(theta)=sin(theta)/cos(theta)=
[-sqroot(3)/2]/(-1/2)= + sqroot(3)=
sqroot(3)
ctg(theta)=1/tan(theta)=1/sqroot(3)
sec(theta)=1/cos(theta)=1/(-1/2)= -2
cosec(theta)=1/sin(theta)=1/[-sqroot(3) /2]= -2/sqroot(3)
quadrant,negative in II and III quadrant.
The tangent is positive in I and III guadrant,negative in II and IV quadrant.
If cos(theta)<0 cosine is negative
If tan(theta)>0 tangent is positive
Only quadrant where cosine is nagative,and tangent is positive is quadrant III.
sin(theta)= + OR - sqroot[1-cos^2(theta)]
In quadrant III sine is negative so:
sin(theta)= - sqroot[1-cos^2(theta)]
sin(theta)= - sqroot[1-(-1/2)^2]
sin(theta)= - sqroot(1-1/4)
sin(theta)= - sqroot(3/4)
sin(theta)= - sqroot(3) /2
tan(theta)=sin(theta)/cos(theta)=
[-sqroot(3)/2]/(-1/2)= + sqroot(3)=
sqroot(3)
ctg(theta)=1/tan(theta)=1/sqroot(3)
sec(theta)=1/cos(theta)=1/(-1/2)= -2
cosec(theta)=1/sin(theta)=1/[-sqroot(3) /2]= -2/sqroot(3)
Answered by
anna
determine all trig functions of theta using the given info, state the answers correct to the nearest hundredth.
cos (theta) = -5/13; tan (theta) < 0
cos (theta) = -5/13; tan (theta) < 0
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