Asked by Laura
This is the questions I have trouble with :
Set up (do not evaluate) the integral that gives the surface area of the surface generated by rotating the curve y=tanhx on the interval (0, 1) around the x-axis.
Anyone who can help? Not really sure how to even begin!
Thanks
Set up (do not evaluate) the integral that gives the surface area of the surface generated by rotating the curve y=tanhx on the interval (0, 1) around the x-axis.
Anyone who can help? Not really sure how to even begin!
Thanks
Answers
Answered by
bobpursley
Surface area will be y dx dTheta
from x 0 to 1, and theta from 0 to 2PI
Area= Int (Int) tanhx dx dtheta
Answered by
Mgraph
Area=2Pi(int from 0 to 1) y*sqrt(1+(y')^2)dx
Answered by
Laura
Thanks so much! :)
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