Asked by Brittany
I have to solve this equation by extracting square roots.
(x-7)^2=(x+3)^2
(x-7)^2=(x+3)^2
Answers
Answered by
Reiny
take the square root of both sides to get
±(x-7) = ±(x+3) which resolves into
x+7 = x+3 or x+7 = -x-3
the first gives no solution but the second part yields
x = 2
Check:
Left side = (2-7)^2
=(-5)^2
=25
Right side = (2+3)^2
= 25
so x=2 is the correct solution
±(x-7) = ±(x+3) which resolves into
x+7 = x+3 or x+7 = -x-3
the first gives no solution but the second part yields
x = 2
Check:
Left side = (2-7)^2
=(-5)^2
=25
Right side = (2+3)^2
= 25
so x=2 is the correct solution
Answered by
Brittany
Maybe I am not getting how you are getting 2 because I keep getting 5 when I try to solve for x+7=-x-3. It turns out like 2x=-10
Answered by
Brittany
Never mind, I got it now.
Answered by
Reiny
my typo error, sorry
should have said x-7 = -x-3
2x = 4 ......
should have said x-7 = -x-3
2x = 4 ......
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